Answer:
Following are the responses to the given question:
Explanation:
[tex]\to C_6H_9NO[/tex]
calculating the HOI:
[tex]= \frac{2C+2+N-H-X}{2} \\\\ =\frac{2\times 6+2+1-9-0}{2}\\\\ =\frac{12-6}{2}\\\\=\frac{6}{2}\\\\=3[/tex]
So, in the above compund there are three bounds or we can say that one is double and two bound is single.
Please find the attachment file of the Function group:
In the above given conditon compound doesn't include the alkene functional group that is absense of[tex]-C=C-[/tex] , and compound include [tex]-C\equiv C-[/tex] So, please find the attached file of the structure of the compound:
