Answer:
Percent Increase in measure of the side of a square = 30%
Step-by-step explanation:
Let the measure of the side of a square = s
Area of the square = (Side)²
= s²
If the area of the square is increased by 69%
Area of the new square = s² + 69% of s²
= s² + 0.69s²
= 1.69s²
Therefore, measure of the side of the new square = √(Area of the square)
= √(1.69s²)
= 1.3s
Measure of side of the old square = s
Therefore, increase in measure of the square = 1.3s - s
= 0.3s
Percent increase in the measure of the side of the square
= [tex]\frac{\text{Increase in measure}}{\text{Measure of the side of the original square}}\times 100[/tex]
= [tex]\frac{0.3s}{s}\times 100[/tex]
= 30%
