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How many moles of the Htion in 395 mL of 1.325 M sulfuric acid (H2SO4).
Assume the acid fully dissociates.

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dsdrajlin

Answer:

1.05 mol

Explanation:

Step 1: Given data

  • Molarity of sulfuric acid (M): 1.325 M (1.325 mol/L)
  • Volume of solution (V): 395 mL (0.395 L)

Step 2: Calculate the moles of sulfuric acid (n)

We will use the following expression.

M = n/V

n = M × V

n = 1.325 mol/L × 0.395 L = 0.523 mol

Step 3: Calculate the moles of H⁺

H₂SO₄ dissociates completely according to the following equation.

H₂SO₄ ⇒ 2 H⁺ + SO₄²⁻

The molar ratio of H₂SO₄ to H⁺ is 1:2. The moles of H⁺ are 2/1 × 0.523 mol = 1.05 mol.

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