Triangle ABC is formed by two parallel lines and two other intersecting lines. Find the measure of each angle A, B, and of the triangle.

Answer:
A = 61°
B = 72°
C = 47°
Step-by-step explanation:
Well, first of all, we can see that:
[tex]61^{\circ}+47^{\circ}+B^{\circ}=180^{\circ}[/tex]
So, we can find angle B.
[tex]B=180^{\circ}-47^{\circ}-61^{\circ}[/tex]
[tex]B=72^{\circ}[/tex]
Now, we can see to that angle C is just 47°
Finally, we know that the sum of all angles in a triangle is 180°, so we have:
[tex]B+A+C=180^{\circ}[/tex]
[tex]A=180^{\circ}-47^{\circ}-72^{\circ}[/tex]
[tex]A=61^{\circ}[/tex]
I hope it helps you!
The measure of each angle ∠A, ∠B, and ∠C of the triangle. are 61, 72, and 47 degrees.
Angle is the space between the line or the surface that meets. And the angle is measured in degree. For complete 1 rotation, the angle is 360 degrees.
Triangle ABC is formed by two parallel lines and two other intersecting lines.
The angle ∠A and angle 61 are equal because they are corresponding angles. Then angle ∠A will be
∠A = 61
The angle ∠C and angle 47 are equal because they are Alternate angles. Then angle ∠C will be
∠C = 47
We know that the sum of all the interior angles of a triangle is equal to 180 degrees.
∠A + ∠B + ∠C = 180
61 + ∠B + 47 = 180
On simplifying, we have
∠B = 72
Thus, the measure of each angle A, B, and of the triangle. are 61, 72, and 47 degrees.
More about the angle link is given below.
https://brainly.com/question/15767203