Answer:
3 long whiskers: 1 short whiskers
Explanation:
This question involves a single gene coding for whiskers length in a certain animal. The allele for long whiskers (W) is dominant over the allele for short whiskers (w). This means that a heterozygous individual (Ww) will possess a long whisker.
According to this question, a heterozygous female with long whiskers (Ww) mates with a heterozygous male with long whiskers (Ww). The proportion of offsprings that will be produced from this cross (see punnet square) is as follows:
WW, Ww, Ww, ww
WW, Ww, Ww offsprings will possess a long whisker while 'ww' offspring will possess a short whisker. Hence, the phenotypic ratio will be 3 long whiskers: 1 short whiskers
