just need help with the way. thanks!

Answer:
KN ≈ 20.7 cm
Step-by-step explanation:
Using Pythagoras' identity in right triangle KLM to find KM
LM² = KL² + KM²
28² = 16² + KM²
784 = 256 + KM² ( subtract 256 from both sides )
528 = KM² ( take the square root of both sides )
[tex]\sqrt{528}[/tex] = KM
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Using the sine ratio in right triangle KMN
sin64° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{KN}{KM}[/tex] = [tex]\frac{KN}{\sqrt{528} }[/tex] ( multiply both sides by [tex]\sqrt{528}[/tex]
[tex]\sqrt{528}[/tex] × sin64° = KN , that is
KN ≈ 20.7 cm ( to 1 dec. place )