Answer:
The maximum error in the calculated surface area is approximately 8.3083 square centimeters.
Step-by-step explanation:
The circumference ([tex]s[/tex]), in centimeters, and the surface area ([tex]A_{s}[/tex]), in square centimeters, of a sphere are represented by following formulas:
[tex]A_{s} = 4\pi\cdot r^{2}[/tex] (1)
[tex]s = 2\pi\cdot r[/tex] (2)
Where [tex]r[/tex] is the radius of the sphere, in centimeters.
By applying (2) in (1), we derive this expression:
[tex]A_{s} = 4\pi\cdot \left(\frac{s}{2\pi} \right)^{2}[/tex]
[tex]A_{s} = \frac{s^{2}}{\pi^{2}}[/tex] (3)
By definition of Total Differential, which is equivalent to definition of Linear Approximation in this case, we determine an expression for the maximum error in the calculated surface area ([tex]\Delta A_{s}[/tex]), in square centimeters:
[tex]\Delta A_{s} = \frac{\partial A_{s}}{\partial s} \cdot \Delta s[/tex]
[tex]\Delta A_{s} = \frac{2\cdot s\cdot \Delta s}{\pi^{2}}[/tex] (4)
Where:
[tex]s[/tex] - Measure circumference, in centimeters.
[tex]\Delta s[/tex] - Possible error in circumference, in centimeters.
If we know that [tex]s = 82\,cm[/tex] and [tex]\Delta s = 0.5\,cm[/tex], then the maximum error is:
[tex]\Delta A_{s} \approx 8.3083\,cm^{2}[/tex]
The maximum error in the calculated surface area is approximately 8.3083 square centimeters.
