Answer:
[tex]\pi 1 = \frac{h}{l}[/tex]
[tex]\pi 2 =[/tex] б / [tex]l^2gp[/tex]
[tex]\frac{h}{l} =[/tex] Ф ( б / [tex]l^2gp[/tex] )
Explanation:
Develop a suitable set of dimensionless parameters for this problem
The set of dimensionless parameters for this problem is :
[tex]\pi 1 = \frac{h}{l}[/tex]
[tex]\pi 2 =[/tex] б / [tex]l^2gp[/tex]
[tex]\frac{h}{l} =[/tex] Ф ( б / [tex]l^2gp[/tex] )
and they are using the pi theorem, MLT systems
attached below is a detailed solution