Answer:
0.32 = 32% probability that an employee selected at random will need either corrective shoes or major dental work.
Step-by-step explanation:
We solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Needing corrective shoes.
Event B: Needing major dental work.
14% of the employees needed corrective shoes
This means that [tex]P(A) = 0.14[/tex]
21% needed major dental work
This means that [tex]P(B) = 0.21[/tex]
3% needed both corrective shoes and major dental work.
This means that [tex]P(A \cap B) = 0.03[/tex]
What is the probability that an employee selected at random will need either corrective shoes or major dental work?
This is:
[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]
So, from the values given by the exercise:
[tex]P(A \cup B) = 0.14 + 0.21 - 0.03 = 0.32[/tex]
0.32 = 32% probability that an employee selected at random will need either corrective shoes or major dental work.
