Answer:
The area of the warehouse B is 1150 square feet.
Step-by-step explanation:
Let [tex]x[/tex], [tex]y[/tex] are the width and length of the warehouse A, in inches. The areas of the each warehouse are described below:
[tex]A_{A} = x\cdot y[/tex] (1)
[tex]A_{B} = \left(\frac{1}{2}\cdot x \right)\cdot \left(\frac{1}{3}\cdot y \right)[/tex] (2)
Where:
[tex]A_{A}[/tex] - Area of the warehouse A, in square inches.
[tex]A_{B}[/tex] - Area of the warehouse B, in square inches.
If we know that [tex]A_{A} = 6900\,ft^{2}[/tex], then by (1) and (2) we have the following equation:
[tex]A_{B} = \frac{1}{6}\cdot A_{A}[/tex]
[tex]A_{B} = 1150\,ft^{2}[/tex]
The area of the warehouse B is 1150 square feet.
