Answer:
The system is of equations is:
[tex]\left\{ \begin{array}{ll} 10g+15r=725 & \quad \\ g+r=60 & \quad \end{array} \right.[/tex]
Where g is the amount of general tickets and r is the amount of reserve tickets.
35 general tickets and 25 reserve tickets were sold.
Step-by-step explanation:
Let general tickets be represented by g and reserved tickets be represented by r.
Each general ticket sells for $10 each and reserved tickets $15 each. Dave collected a total of $725. Thus:
[tex]10g+15r=725[/tex]
And a total of 60 tickets were sold. Hence:
[tex]g+r=60[/tex]
Our system of equations is:
[tex]\left\{ \begin{array}{ll} 10g+15r=725 & \quad \\ g+r=60 & \quad \end{array} \right.[/tex]
We can solve by substitution. First, divide both sides of the first equation by 5:
[tex]2g+3r=145[/tex]
Next, we can subtract a variable (r in this case) from the second equation:
[tex]g=60-r[/tex]
Substitute:
[tex]2(60-r)+3r=145[/tex]
Distribute:
[tex]120-2r+3r=145[/tex]
Simplify:
[tex]120+r=145[/tex]
Subtract:
[tex]r=25[/tex]
Using the previous equation:
[tex]g=60-r[/tex]
Substitute and evaluate:
[tex]g=60-(25)=35[/tex]
So, 35 general tickets and 25 reserve tickets were sold.
