If the He H e injected into the abdomen produces a pressure of 22 mmHg m m H g and a volume of 2.7 L L at 31 ∘C ∘ C , how many grams of He H e were used?

Respuesta :

Answer:

1280.27 g

Explanation:

Pressure = 22 mmHg / 760 = 0.0289 atm (Converting to atm by dividing by 760)

Volume = 2.7 L

Temperature = 31 ∘C + 273 = 304 K

Mass = ?

Using the ideal gas equation;

PV = nRT

n = RT / PV = 0.0821 * 304 / ( 0.0289 * 2.7)

n = 319.86 mol

Mass = Number of moles * Molar mass

Mass = 319.86  * 4.002602

Mass = 1280.27 g