We have to find out the probability of getting 6 and 3,
Since this only one roll it is not possible to get 2 numbers in one roll
So, I will presume you want the probability of getting 6 or 3,
Total number of outcomes= {1,2,3,4,5,6} = 6 outcomes
Number of favorable outcomes = {3,6} = 2 outcomes
Probability of rolling 6 or 3 = [tex]\frac{Number'of 'favorable' outcomes}{Total' number 'of' outcomes}[/tex]
= 2/6
= 1/3 or 0.33333%
Therefore the probability of rolling 6 or 3 is one in three chances
Happy to help :)
If u have any doubts or questions , feel free to ask
