The given question is incomplete. The complete question is:
Ammonium phosphate [tex](NH_4)_3PO_4[/tex] is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid [tex]H_3PO_4[/tex] with liquid ammonia. Calculate the moles of ammonium phosphate produced by the reaction of 1.7 mol of ammonia. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.
Answer: 0.57 moles of ammonium phosphate are produced by the reaction of 1.7 moles of liquid ammonia
Explanation:
The balanced chemical equation is:
[tex]H_3PO_4+3NH_4OH\rightarrow (NH_4)_3PO_4+3H_2O[/tex]
According to stoichiometry:
3 moles of liquid ammonia [tex](NH_4OH)[/tex] produces = 1 mole of ammonium phosphate [tex](NH_4)_3PO_4[/tex]
Thus 1.7 moles of liquid ammonia [tex](NH_4OH)[/tex] produces = [tex]\frac{1}{3}\times 1.7=0.57[/tex] mole of ammonium phosphate [tex](NH_4)_3PO_4[/tex]
Thus 0.57 moles of ammonium phosphate are produced by the reaction of 1.7 moles of liquid ammonia