theyluvaidan
contestada

Mandy's dog will be having four puppies. Mandy performs
a simulation by tossing a coin to model whether these
puppies will be male or female.
• Let heads (H) = female puppy
• Let tails (T) = male puppy
The results of the simulation are:
1. THTT
6. HHHH
2. TTTH
7.HTHT
3. TTHH 8. HHHT
4. HTTT
9. THTH
5. TTTT
10. HHHH
What is the estimated probability that at least two of the puppies will be
female?
A. ) = 70%
B. 6 = 60%
30%
D.
50%

Respuesta :

Answer: C 30 it was correct on my test

The estimated probability that at least two of the puppies will be female is 60%.

What is probability?

Probability deals with the occurrence of a random event. The chance that a given event will occur. It is the measure of the likelihood of an event to occur.The value is expressed from zero to one.

For the given situation,

Let heads (H) be the female puppy

Let tails (T) be the male puppy.

The simulation results are the sample spaces.

[tex](THTT, TTTH, TTHH, HTTT, TTTT, HHHH, HTHT, HHHT, THTH, THTH)[/tex]

⇒ [tex]n(s)=10[/tex]

The event is the probability that at least two of the puppies will be

female.

[tex]e=(TTHH, HHHH, HTHT, HHHT, THTH, THTH )\\[/tex]

⇒ [tex]n(e)=6[/tex]

The estimated probability that at least two of the puppies will be

female, [tex]P(e)=\frac{n(e)}{n(s)}[/tex]

⇒ [tex]P(e)=\frac{6}{10}[/tex]

⇒ [tex]P(e)=0.6[/tex]

Thus the percentage of the female puppies = [tex](0.6)(100)[/tex]

⇒ [tex]60\%[/tex]

Hence we can conclude that the estimated probability that at least two of the puppies will be female is 60%.

Learn more about probability here

https://brainly.com/question/16086035

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