Answer:
The appropriate response is "0.9476".
Step-by-step explanation:
The given values are:
Standard deviation,
[tex]\sigma=1150[/tex]
Randomly selected railroad-car shipments,
n = 500
As we know,
⇒ [tex]\sigma \bar{x}=\frac{\sigma}{\sqrt{n} }[/tex]
On substituting the values, we get
⇒ [tex]=\frac{1150}{\sqrt{500} }[/tex]
then,
⇒ [tex]=P(-1.94<Z<1.94)[/tex]
⇒ [tex]=P(Z<1.94)-P(Z < -1.94)[/tex]
On using the table of P, we get
⇒ [tex]=0.9738 - 0.0262[/tex]
⇒ [tex]=0.9476[/tex]