Answer: The theoretical yield of potassium chloride is 0.596 grams and the % Yield of potassium chloride is 83.9%
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} KClO_3=\frac{1.00g}{122.5g/mol}=0.008moles[/tex]
[tex]2KClO_3\rightarrow 2KCl+3O_2[/tex]
According to stoichiometry :
2 moles of [tex]KClO_3[/tex] produce= 2 moles of [tex]KCl[/tex]
Thus 0.008 moles of [tex]KClO_3[/tex] will produce=[tex]\frac{2}{2}\times 0.008=0.008moles[/tex] of [tex]KCl[/tex]
Theoretical yield of [tex]KCl=moles\times {\text {Molar mass}}=0.008moles\times 74.5g/mol=0.596g[/tex]
% yield = [tex]\frac{\text {Actual yield}}{\text {Theoretical yield}}\times 100=\frac{0.500g}{0.596g}\times 100\%=83.9\%[/tex]
The theoretical yield of potassium chloride is 0.596 grams and the % Yield of potassium chloride is 83.9%