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Central Fencing has been hired to fence the perimeter of a rectangular field. The length of the field is 42 - W feet, where W is the width of the field, and the area of the field must be more than 432 square feet. Find the bounds on the width of the field.

Respuesta :

Answer:

10.3 is the width

Step-by-step explanation:

set up an equation

42w=432

divided both sides by 42

W=10.2857142857

to rounded it to nearest tenth it will be 10.3

to check your answer multiply 10.3 by 42 it will be 432

check check

hnhan369963oshi04

Answer:

18 ≤ w ≤ 24

Step-by-step explanation:

A = l * w

A ≥ 432 sq ft.

l = 42 - w

432 ≤ (42 - w) (w)

432 ≤ -w² + 42w

w² - 42w ≥ 432

Substitute values for w

w = 18

w = 24

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