Answer: [tex]1.298\times 10^{-5}\ N/m[/tex]
Explanation:
Given
Current in the first wire [tex]I_1=2.2\ A[/tex]
Current in the second wire [tex]I_2=5.9\ A[/tex]
wires are [tex]20\ cm[/tex] apart
Force per unit length between the current-carrying wires is
[tex]\Rightarrow \dfrac{F}{l}=\dfrac{\mu_oI_1I_2}{2\pi r}[/tex]
Force exerted by the wires is the same
Put the values
[tex]\Rightarrow \frac{F}{l}=f=\dfrac{4\pi \times 10^{-7}\times 2.2\times 5.9}{2\pi \times 0.2}=1.298\times 10^{-5}\ N/m[/tex]
This force will be repulsive in nature as the current is flowing opposite
