Answer:
P₂ = 2.04 atm
Explanation:
Given that,
Initial volume, V₁ = 10.2 L
Initial pressure, P₁ = 0.6 atm
Final volume, V₂ = 3 L
We need to find the final pressure. The relation between the pressure and the volume is given by :
[tex]P_1V_1=P_2V_2\\\\P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{10.2\times 0.6}{3}\\\\P_2=2.04\ atm[/tex]
So, the new pressure is equal to 2.04 atm.
