Given:
The expression is:
[tex](x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}[/tex]
To find:
The value of the given expression when [tex]x=64[/tex] and [tex]y=27[/tex].
Solution:
We have,
[tex](x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}[/tex]
Putting [tex]x=64[/tex] and [tex]y=27[/tex], we get
[tex]=((64)^2(27)-3)^0+(64)^{\frac{1}{3}}-(4(64))^{\frac{1}{2}}[/tex]
It can be written as
[tex]=((64)^2(27)-3)^0+(4^3)^{\frac{1}{3}}-(4)^{\frac{1}{2}}(64)^{\frac{1}{2}}[/tex]
[tex]=1+4-2(8)[/tex] [tex][\because a^0=1,a\neq 0][/tex]
[tex]=5-16[/tex]
[tex]=-11[/tex]
Therefore, the value of the given expression [tex]-11[/tex] when [tex]x=64[/tex] and [tex]y=27[/tex].
