Four charges of equal charge+q are placed at the corners of a rectangle of sides a and b.
What is the potential at the center of the rectangle if q = 2.0 uc, a = 3.0 cm, and b = 4.0cm?​

Respuesta :

Answer:

V = 32.2 10³ V

Explanation:

The electric potential is a scalar quantity given by the expression

          V = h ∑  [tex]\frac{ q_i}{r_i}[/tex]

Let's find the distance from each corner to the center of the square, using Pythagoras' theorem

           r = [tex]\frac{1}{2} \sqrt{a^2 + b^2}[/tex]

       

indicate that all charges have the same magnitude and the casticista from each scheme to the center is r

           V = k q ([tex]\frac{4}{r}[/tex])

let's calculate

            r = ½ [tex]\sqrt{2^2 + 4^2}[/tex]Ra 2² + 4²

            r = 2,236 m

           V = 9 10⁹ 2 10⁻⁶  4 / 2,236

           V = 32.2 10³ V