Two identical positive charges exert a repulsive force of 6.4x10^-9 N when separated by a distance of 3.8x10^10 m. Calculate the charge of each.

Respuesta :

Answer:F = kq2/d2 ⇒

q = √(Fd2/k)

q = d √(F/k)

d = 3.8 x 10-10 m

F = 6.4 x 10-9 N

Look up k in your physics book in appropriate units, and plug in the numbers. You should get q in coulombs.

Explanation:

The value of each charge will be 1.64 ×10⁻⁴. The concept of the columb force is used.

What is the charge?

When the matter is put in an electromagnetic field, it has an electric charge, which causes it to experience a force. A positive or negative electric charge can exist.

Charges that are similar repel each other, whereas charges that are dissimilar attract each other. The term "neutral" refers to an item that has no net charge.

[tex]\rm F =K \frac{q_1Q_2}{d^2} \\\\ F = K\frac{q^2}{d^2} \\\\ q = \sqrt{\frac{dF}{k} } \\\\ q = \sqrt{\frac{3.8 \times 10^{10}\times 6.4 \times 10^{-9}}{9 \times 10^9} } \\\\ q=1.64 \times 10-4[/tex]

Hence the value of each charge will be 1.64 ×10⁻⁴. The concept of the columb force is used.

To learn more about the charge refer to the link;

https://brainly.com/question/24391667