Answer:
Peach and Apple will take the same time as the gravitional pull acting on both of them is equal.
height of peach=initial velocity*time+1/2*gravitional pull*(time^2)
1.8=0*time+1/2*9.8*time^2
1.8=0+1/2*9.8*time^2
1.8=1/2*9.8*time^2
3.6/9.8=time^2
taaking value of gravitional pull approx to 10
3.6/10=time^2
0.36=time^2
0.6=time
therefore, the time taken is 0.6sec
Explanation:
The time it takes the peach to reach the ground is 0.61 sec
From the question,
We are to determine how long it would take the peach to reach the ground.
From one of the equations of kinematics for free falling objects,
We have that
[tex]H = ut + \frac{1}{2}gt^{2}[/tex]
Where
H is the height
u is the initial velocity,
t is the time
and g is the acceleration due to gravity ( g = 9.8 m/s²)
Since the object is dropped with no velocity, then the initial velocity is 0 m/s
From the given information
H = 1.8 m
u = 0 m/s
Putting the parameters into the formula,
We get
[tex]1.8 = 0(t) + \frac{1}{2}(9.8)t^{2}[/tex]
This becomes
[tex]1.8 = 0 + 4.9t^{2}[/tex]
[tex]1.8 = 4.9t^{2}[/tex]
Then,
[tex]t^{2} = \frac{1.8}{4.9}[/tex]
[tex]t^{2} = 0.367347[/tex]
∴ [tex]t =\sqrt{0.367347}[/tex]
t = 0.60609 sec
t ≅ 0.61 sec
Hence, the time it takes the peach to reach the ground is 0.61 sec
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