Answer:
32 siblings from the class theres a possibility that some students had more siblings and not everyone has one
Step-by-step explanation:
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The probability that a student chosen randomly from the class has a brother and a sister is [tex]\frac{1}{15}[/tex].
The chance that something will happen, or how likely it is that an event will occur.
probability of an event = [tex]\frac{number of favorable outcomes}{Total number of outcomes}[/tex]
According to the given question
we have total 30 students.
6 have a brother
12 have a sister
and 14 who don't have any siblings
If we se the provided Venn diagram
the number of students who have only sister is 10
and the number of student who have only brother is 4.
because, 6+12+14 = 32
but we have only 30 students
⇒ 2 students has a brother and a sister.
therefore,
the probability that a student chosen randomly from the class has a brother and a sister = [tex]\frac{number of students as a brother and a sister}{total number of students}[/tex]= [tex]\frac{2}{30}[/tex] =[tex]\frac{1}{15}[/tex]
Hence, the probability that the chosen student from the class has a brother and sister is [tex]\frac{1}{15}[/tex].
Learn more about probability here:
https://brainly.com/question/11234923
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