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chemhelperAZ

Answer:

[tex]CCl_{2}[/tex]

Explanation:

When calculating an empirical formula from percentages, assume you have a 100g sample. This allows you to convert the percentages directly to grams, because X % of 100g is X grams.

So:

14.6% C = 14.6g C, 85.4%Cl = 85.4g Cl

The next step is to divide each mass by their molar mass to convert your grams to moles.

14.6g/12.01 = 1.22 mol

85.4g/35.45= 2.41 mol

Then you will divide all of your mol values by the SMALLEST number of moles. This gives you whole numbers that are the mole ratio (subscripts) of the empirical formula.

1.22 mol/1.22 mol = 1

2.41 mol/1.22 mol = 2

So the empirical formula is

[tex]CCl_{2}[/tex]

samueladesida43

The empirical formula of the compound is CCl2.

HOW IS EMPIRICAL FORMULA CALCULATED:

  • Empirical formula of a compound is the smallest ratio of elements contained in that compound. The steps for calculating the empirical formula are as follows:

  • 14.6% carbon and 85.4% chlorine by mass means the compound has 14.6g of C and 85.4g of Cl

  • First, we divide each mass by their respective molar mass:

C = 14.6g ÷ 12g/mol = 1.22mol

Cl = 85.4g ÷ 35.5g/mol = 2.41mol

  • Next, we divide each mole value by the smallest value:

C = 1.22mol ÷ 1.22 = 1

Cl = 2.41mol ÷ 1.22 = 1.97

Approximately, the carbon to chlorine ratio is 1:2, hence, the empirical formula of the compound is CCl2.

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