Respuesta :

jiyoonkim
1 mole of CO2 has 6.02 x 10^23 molecules of CO2. Say x moles of CO2 has 3.0x10^23 molecules of CO2. Therefore x = 3/6.02 = 0.50. M = 0.50 * (12 + 2x16) = 0.50 * 44 = 22g
okpalawalter8

We have that for the Question "" it can be said that the mass (in grams) of 3.03 × 1024 molecules of carbon dioxide molecules is

  • Amount of CO_2(g)=221.35g

From the question we are told

What is the mass (in grams) of 3.03 × 1024 molecules of carbon dioxide molecules?

Generally the equation for the   is mathematically given as

[tex]No moles in 3*02*10^{24}=\frac{3.03*10^{24}}{6.023*10^-{23}}[/tex]

No moles in 3*02*10^{24}=5.03moles

Amount of CO_2(g)=5.03moles *44g/mol

Amount of CO_2(g)=221.35g

Hence

the mass (in grams) of 3.03 × 1024 molecules of carbon dioxide molecules is

Amount of CO_2(g)=221.35g

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