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A man pulls a sled at a constant velocity across a horizontal snow surface . If a force of 80 n is being applied to the sled at an 53 degree to the ground . What is the force of friction between sled and snow

Respuesta :

Answer:

Explanation:

The force of 80N is applied on sled at 53⁰

Its horizontal  component = 80cos53

= 48.14 N .

Its horizontal component will pull forward the sled and friction will prevent its forward motion . As sled is moving with constant velocity , net force on it is zero .

Hence forward push = frictional force

Frictional force = 48.14 N.

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