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After analyzing the DNA of a colony of bacteria, a scientist concludes that the colony was made of 3764 individual bacteria. For the genetic trait “B,” two alleles are present, B and b. In the colony, there were 4712 occurrences of “b” and 2816 occurrences of “B.”

5. What is the frequency of the B allele? (First, add together the number of b and B to find the total number of alleles. Next, divide the number of B alleles by the total number of alleles.)

6. What is the frequency of the b allele? (First, add together the number of b and B to find the total number of alleles. Next, divide the number of b alleles by the total number of alleles.)

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lavenderlillacs25 lavenderlillacs25 · Answer 1 · 2021-03-26T18:42:39+01:00

Answer: .374 and .626

Explanation:

5. total number of alleles = 4712 + 2816 = 7528

frequencey of B allele = B allele / total number of alleles --> 2816/7528 = 0.374

6. total number of alleles = 4712 + 2816 = 7528

freq of b allele = b allele/total number of alleles --> 4712/7528 = 0.626

We can confirm our answer as correct because if we add up the answers to 5 and 6 we should get one:

0.374 + 0.626 = 1