Answer:
90 Pomegranate and 55 iZac
Step-by-step explanation:
Represent Pomegranate with p and iZac with i
The data can be represented in the following table.
[tex]\begin{array}{cccc}{} & {Pomegranate} & {iZac} & {Total} & {Memory} & {400} & {300} & {52500} & {Disk\ Space} & {80} & {100} & {12700} \ \end{array}[/tex]
The table can be represented as follows:
[tex]400p + 300i = 52500[/tex] --- (1)
[tex]80p + 100i = 12700[/tex] ---- (2)
Multiply equation (2) by 3
[tex]3 *\ ([/tex][tex]80p + 100i = 12700[/tex][tex])[/tex]
[tex]240p + 300i = 38100[/tex] ---- (3)
Subtract (3) from (1)
[tex]400p - 240p + 300i - 300i = 52500 - 38100[/tex]
[tex]160p = 14400[/tex]
Divide both sides by 160
[tex]p = 90[/tex]
Substitute [tex]p = 90[/tex] in (2)
[tex]80p + 100i = 12700[/tex]
[tex]80 * 90 + 100i = 12700[/tex]
[tex]7200 + 100i = 12700[/tex]
Collect like terms
[tex]100i = 12700 - 7200[/tex]
[tex]100i = 5500[/tex]
Divide by 100
[tex]i = 55[/tex]
So;
[tex]p = 90[/tex] and [tex]i = 55[/tex]