Answer:
The answer is below
Step-by-step explanation:
The co-vertices of an ellipse are the endpoints of the minor axis. The equation for an ellipse is given by:
[tex]\frac{(x-h)^2}{a^2} +\frac{(y-k)^2}{b^2}=1[/tex]
Where (h, k) is the center of the ellipse, (h, k±b) is the co-vertices, (h ± a, k) is the vertices, (h ± c, k) is the foci and c² = a² - b²
Since the center is the origin, hence (h, k) = (0, 0). i.e h = 0, k = 0.
Foci = (h ± c, k) = (± c, 0) = (±3, 0). c = 3
co-vertices = (h, k±b) = (0, ±b) = (0, ±4). b = 4
c² = a² - b²
a² = c² + b²
a² = 3² + 4² = 25
a = 5
Therefore the equation of the ellipse is:
[tex]\frac{x^2}{5^2} +\frac{y^2}{4^2}=1 \\\\\frac{x^2}{25} +\frac{y^2}{16}=1[/tex]
