Suzanne is going to rent a car while she is out of town. One car rental company offers a flat rate of $35 per day plus $0.10 per mile. Another car rental company offers the same car for $25 per day plus $0.25 per mile. She will need the car for 5 days. How many miles would she need to drive for the first rental company to be a better deal?

r1 = 35*d + .10*m, rental car company 1r2 = 25*d + .25m, rental car company 2
r1 will be a better deal when when r2 > r1r2 > r1 when35*5 + .10*m > 25*5 + .25m5(35-25) > (.25 - .10)m5*10 > (.15)m50/.15 > mm > 50/.15 = 33 1/3
Ans. When 33 1/3 miles have been driven, rental car company r1 will be a better deal.

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wifilethbridge wifilethbridge · Answer 2 · 2019-10-01T10:28:04+02:00

Answer:

She need to drive more than 2000 miles for the first rental company to be a better deal .

Step-by-step explanation:

Case 1) One car rental company offers a flat rate of $35 per day plus $0.10 per mile

Let m be the no. of miles

She will need the car for 5 days.

So, total cost = [tex]35 \times 5 +0.10m=175+0.10m[/tex]

Case 2) Another car rental company offers the same car for $25 per day plus $0.25 per mile.

Let m be the no. of miles

She will need the car for 5 days.

So, total cost = [tex]25 \times 5 +0.25m=125 +0.25m[/tex]

Now we are supposed to find How many miles would she need to drive for the first rental company to be a better deal?

So, [tex]175+0.10m <125 +0.25m [/tex]

[tex]175+125 <125 +0.25m-0.10m [/tex]

[tex]300 < 0.15m [/tex]

[tex]\frac{300}{0.15} < m [/tex]

[tex]2000 < m [/tex]

So, she need to drive more than 2000 miles for the first rental company to be a better deal