Respuesta :
the answer is
1J, 2J, 3J, ...............29D, 30D, 31D = 365 days
2 4 6 ........................................
let be S the value of entire savings
S= Sum 2K= 2 Sum K = 2 [365(365+1) / 2],
1<K<365 1<K<365
because Sum K = n(n+1) /2
1<K<n
finally S= 133590 pennies
1J, 2J, 3J, ...............29D, 30D, 31D = 365 days
2 4 6 ........................................
let be S the value of entire savings
S= Sum 2K= 2 Sum K = 2 [365(365+1) / 2],
1<K<365 1<K<365
because Sum K = n(n+1) /2
1<K<n
finally S= 133590 pennies