The heat of fusion for water at its normal freezing or melting temperature is L=333 kJ/kg. How much water remains unfrozen after 50.2 kJ is transferred as heat from 260 g of liquid water initially at its freezing point? ...?
50.2 kJ = 333 kJ/kg * mass of water
mass of water is 0.15075075075075075075075075075075 kg
therefore mass of unfrozen water is 0.10924924924924924924924924924925 kg
50.2 kJ = 333 kJ/kg * mass of watermass of water is 0.15075075075075075075075075075075 kgtherefore mass of unfrozen water is 0.10924924924924924924924924924925 kg
