The amount of heat released by 38 g sample of water to freeze is 12692 J
From the question given above, the following data were obtained:
Mass of water (m) = 38 g
Heat of fusion (ΔHf) of water = 334 J/g
Heat (Q) released =?
The heat released by the water can be obtained as follow:
Q = m•ΔHf
Q = 38 × 334
Q = 12692 J
Therefore, the heat released by the water to freeze is 12692 J
Learn more: https://brainly.com/question/87248
