The solution to the problem is as follows:
The force of friction can be calculated using the equation F = uN, where F is the magnitude of the force, u is the coefficient of friction, and N is the normal force. For an inclined plane at 18 degrees above the horizontal, the normal force is given by N = mg cos theta. Putting all the equations together,
F = umg cos theta
F = (0.09)(1250)(9.80) cos(18)
F = 1.05 kN
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