a=(h)/(2)*(b+b^(2))
Since h is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
(h)/(2)*(b+b^(2))=a
Reorder the polynomial b+b^(2) alphabetically from left to right, starting with the highest order term.
(h)/(2)*(b^(2)+b)=a
Factor out the GCF of b from each term in the polynomial.
(h(b(b)+b(1)))/(2)=a
Factor out the GCF of b from b^(2)+b.
(h(b(b+1)))/(2)=a
Multiply h by b to get bh.
((bh)(b+1))/(2)=a
Remove the parentheses from the numerator.
(bh(b+1))/(2)=a
Multiply each term in the equation by 2.
(bh(b+1))/(2)*2=a*2
Simplify the left-hand side of the equation by canceling the common terms.
bh(b+1)=a*2
Multiply a by 2 to get 2a.
bh(b+1)=2a
Divide each term in the equation by (b+1).
(bh(b+1))/(b+1)=(2a)/(b+1)
Simplify the left-hand side of the equation by canceling the common terms.
bh=(2a)/(b+1)
Divide each term in the equation by b.
(bh)/(b)=(2a)/(b+1)/(b)
Remove the common factors that were cancelled out.
h=(2a)/(b+1)/(b)
Simplify the right-hand side of the equation by simplifying each term.
h=(2a)/(b(b+1))
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