An automobile moving along a straight track changes its velocity from 40 m/s to 80 m/s in a distance of 200 m. What is the (constant) acceleration of the vehicle during this time?
Question 13 options:
1) 8.0 m/s
2) 9.6 m/s
3) 12 m/s
4) 6.9 m/s
5) 0.20 m/s
...?

To calculate the acceleration we use a fundamental kinematic equation, which is expressed as:

vf^2=vi^2+2ad

We can write it as follows:

a= (vf^2 - vi^2) / 2d
a = (80^2 - 40^2) / 2(200)
a = 12 m/s^2 ----> OPTION 3

Hope this answers the question. Have a nice day.

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An automobile moving along a straight track changes its velocity from 40 m/s to 80 m/s in a distance of 200 m. What is the (constant) acceleration of the vehicle during this time? Question 13 options: 1) 8.0 m/s 2) 9.6 m/s 3) 12 m/s 4) 6.9 m/s 5) 0.20 m/s ...?

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An automobile moving along a straight track changes its velocity from 40 m/s to 80 m/s in a distance of 200 m. What is the (constant) acceleration of the vehicle during this time?
Question 13 options:
1) 8.0 m/s
2) 9.6 m/s
3) 12 m/s
4) 6.9 m/s
5) 0.20 m/s
...?