Answer:
[tex]F(64)=2[/tex]
Step-by-step explanation:
Given the funtion:
[tex]F(x)=log_8(64)[/tex]
We need to find the value of the function at x=64:
[tex]F(64)=log_8(64)= z[/tex]
Where z is the value we are trying to find. In order to find z, let's use the definition of the base of a log:
[tex]log_xy=z\Rightarrow x^z=y[/tex]
So:
[tex]8^z=64[/tex]
Express [tex]8^z[/tex] as:
[tex]2^{3z}[/tex]
And express 64 as:
[tex]2^6[/tex]
Which leads to:
[tex]2^{3z}=2^6[/tex]
Equate exponents of 2 on both sides:
[tex]3z=6[/tex]
Solving for z:
[tex]z=\frac{6}{3} =2[/tex]
Therefore:
[tex]F(64)=log_8(64)= z=2[/tex]
