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The total energy need during pregnancy is normally distributed, with mean Mu = 2600 kcal/day and standard deviation = 50 kcal/day. What is the probability that a randomly selected pregnant woman has an energy need of more than 2625 kcal/day? ...?

Respuesta :

This is a normal distribution and we can use the standard score to compute for probabilities. We compute the standard score of the given.

z = (x - mu)/sd
z = (2625 - 2600)/50 = 25/50 = 0.5.

Consulting the z-table, P(z <= 0.5) = 0.6915.
P(z > 0.5) = 1 - P(z <= 0.5) = 1 - 0.6915 = 0.3085.

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