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the captain of a ship views the top of a lighthouse at an angle of 60degree with the horizontal at an elevation of of 6 meters above sea level.five minutes later,the same captain of the ship views the top of the same lighthouse at an angle of 30degree with the horizontal.determine the speed of the ship if the lighthouse is known to be 50 meters above sea level. ...?

Respuesta :


As viewed on the deck, the lighthouse is 50-6 = 44 m above. First we need to compute the two distances from the captain and the lighthouse. For point1:

d1 = 44 / tan(60) = 25.403 m

For point2:
d2 = 44 / tan(30) = 76.210 m

The distance traveled by the ship in five minutes is 50.807 m or 0.050807 km. Five minutes is equivalent to 1/12 hours.

The speed is then equal to 0.050807/(1/12) kph = 0.61 kph.

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