prove tan3A= (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) ...?

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22-11-2016
Mathematics

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prove tan3A= (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) ...?

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Аноним Аноним · Answer 1 · 2016-11-25T14:04:37+01:00

The solution to the problem is as follows:

cos2A - cos4A = -2 sin(6A/2).sin(-2A/2) = +2 sin(3A).sinA

and

sin4A - sin2A = 2 cos(6A/2).sin(2A/2) = 2 cos(3A).sinA

Hence RHS = (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) = sin 3A / cos 3A = tan 3A = LHS

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