Bones23
contestada

Two mechanics worked on a car. The first mechanic worked for
20
hours, and the second mechanic worked for
15
hours. Together they charged a total of
$2000
. What was the rate charged per hour by each mechanic if the sum of the two rates was
$115
per hour?
what is the first mechanics $ per hour? and what was the second mechanics $ per hour?

Respuesta :

20x + 15y = 2000
x + y = 115
55+60=115

20 (55) + 15 (60)=2000
1100+900=2000
2000=2000

x=price per hour for first mechanic

y=price per hour for second mechanic


20x+15y=2000

x+y=115

solve

divide first equation by 5

4x+3y=400


multiply second equation by -3 and add to second


4x+3y=400
-3x-3y=-345 +
1x+0y=55

x=55


x+y=115

55+y=115

minus 55

y=60


first mechanic rage is $55 per hour

second mechanic is $60 per hour