Answer:
[tex]\text{The solution is }x=-4\pm i[/tex]
Step-by-step explanation:
Given the equation
[tex]2x^2+16x+34=0[/tex]
we have to find the solutions of above equation
[tex]2x^2+16x+34=0[/tex]
Comparing it with standard quadratic equation [tex]ax^2+bx+c=0[/tex]
a=2, b=16, c=34
The solution is
[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
[tex]x=\frac{-16\pm \sqrt{16^2-4(2)(34)}}{2(2)}[/tex]
[tex]x=\frac{-16\pm \sqrt{-16}}{4}[/tex]
[tex]x=-4\pm i[/tex]
[tex]\text{The solution is }x=-4\pm i[/tex]
