Answer:
option b
Step-by-step explanation:
We have an equation of circle
[tex](x-7)^2+(y-8)^2=121[/tex]
We have to find the center of given circle and radius
We know that general equation of circle with circle (a,b) and radius r
[tex](x-a)^2+(y-b)^2=r^2[/tex]
[tex](x-7)^2+(y-8)^2=(11)^2[/tex]
By comparing given equation with the general equation of circle
We get centre at x=7 and y=8
Radius =11
Hence, the circle is centered at (7,8) and has a radius of 11.
Option b is true
