Respuesta :
Just took the test, the answer is; [tex] \sqrt 9 + \sqrt 9 = 2 \sqrt9 and \frac{1}{3} + \frac{1}{3} = \frac{2}{3}
[/tex]
Answer: [tex]\sqrt{9} + \sqrt{9} = 2\sqrt{9}[/tex]
[tex]\frac{1}{3} + \frac{1}{3} = \frac{2}{3}[/tex]
Step-by-step explanation:
Since, according to the property that rational numbers are closed under addition.
If a and b are the rational number then (a+b) must be a rational number.
Since, In First option [tex]\sqrt{9} + \sqrt{9} = 2\sqrt{9}[/tex]
Addends √ 9 and √ 9 are rational number.
Also, 2 √9 is the rational number.
Thus It is following the property.
In Second option [tex]\frac{1}{3} + \frac{1}{3} = \frac{2}{3}[/tex]
Addends [tex]\frac{1}{3}[/tex] and [tex]\frac{1}{3}[/tex] are rational numbers.
Also, [tex]\frac{2}{3}[/tex] is a rational number.
Thus, It is also following the property.
Note: Both √6 and √2 are the irrational numbers.
This is why we did not take them.