brAletianynaa brAletianynaa
  • 24-11-2016
  • Mathematics
contestada

Assume the random variable X is normally distributed with a mean of 50 and a standard deviation of 7. Find the 96th percentile.

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syed514
syed514 syed514
  • 26-11-2016
90% then z = invNorm(.90) = 1.2816
z = 1.2816 = (X-50)/77(1.2816) + 50 = 8.97 + 50 = X = 59
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