Answer:
Moles of magnesium present is 0.0833 moles
Explanation:
Magnesium reacts with oxygen to form magnesium oxide.
[tex]2Mg + O_2 \rightarrow 2MgO[/tex]
Amount of magnesium = 2 g
Molar mass of magnesium = 24 g/mol
No. of moles of magnesium [tex]=\frac{2}{24} = 0.0833\ mol[/tex]
So, moles of magnesium present is 0.0833 moles
The number of moles of magnesium present in the reaction is 0.083 mole.
The given parameters;
The chemical reaction of the given elements is written as;
[tex]2Mg \ \ + \ \ O_2 \ \ ---> \ \ 2MgO[/tex]
From the reaction above;
2(24) -------------------------- 2 moles of magnesium
2 -------------------------------- ?
[tex]no\ of \ moles = \frac{2\times 2}{2(24)} = 0.083 \ mole[/tex]
Thus, the number of moles of magnesium present in the reaction is 0.083 mole.
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