Answer:
Radius of the loop, r = 0.12 m
Explanation:
It is given that,
Current flowing in the wire, I = 15 A
Magnetic field at the center of the loop, B = 80 μT = 80 × 10⁻⁶ T
The magnetic field at the center of the circular loop is given by :
[tex]B=\dfrac{\mu_0I}{2r}[/tex]
R is the radius of loop
[tex]r=\dfrac{\mu_oI}{2B}[/tex]
[tex]r=\dfrac{4\times 3.14\times 10^{-7}\times 15}{2\times 80\times 10^{-6}}[/tex]
r = 0.12 m
So, the radius of the loop is 0.12 m
Hence, this is the required solution.
