We will take that gravitational acceleration is 9.81 m/s^2
Gravitational acceleration will drop objects speed (if object stops it will start going down)
now we calculate how much speed will it drop in 3 seconds
ΔV = 3*9.81 = 29.43
From starting speed we subtract ΔV
V -ΔV = 19.8-29,43 = -9,63
Approximately, this means that V = 9.8m/sec downwards because speed is negative.
Answer is B
